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16x^2=484
We move all terms to the left:
16x^2-(484)=0
a = 16; b = 0; c = -484;
Δ = b2-4ac
Δ = 02-4·16·(-484)
Δ = 30976
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{30976}=176$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-176}{2*16}=\frac{-176}{32} =-5+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+176}{2*16}=\frac{176}{32} =5+1/2 $
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